The value of m for which the lines 3x=y-8 and 6× +my +16=0 coincide is
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Given equations are 3x=y-8 and 6x+my+16=0
⇒3x-y+8=0 and 6x+my+16=0
Let a₁=3,b₁=-1,c₁=8 and a₂=6,b₂=m,c₂=16.
If two lines coincide, then a₁/a₂=b₁/b₂=c₁/c₂.
⇒3/6=(-1)/m=8/16
⇒1/2=-1/m
⇒m=-2
Therefore, the value of m is '-2'.
⇒3x-y+8=0 and 6x+my+16=0
Let a₁=3,b₁=-1,c₁=8 and a₂=6,b₂=m,c₂=16.
If two lines coincide, then a₁/a₂=b₁/b₂=c₁/c₂.
⇒3/6=(-1)/m=8/16
⇒1/2=-1/m
⇒m=-2
Therefore, the value of m is '-2'.
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