An object is placed at a distance of 15 cm in front of a convex mirror of focal length 30 cm. Find the nature and position of the image
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object distance u= -15cm
focal length = +30cm as mirror is convex
by mirror formula:
1/f= 1/v + 1/u
1/30= 1/v -1/15
1/30 + 1/15= 1/v
3/30= 1/v
1/10= 1/v
therefor v = +10cm
nature of image is virtual and erect.
focal length = +30cm as mirror is convex
by mirror formula:
1/f= 1/v + 1/u
1/30= 1/v -1/15
1/30 + 1/15= 1/v
3/30= 1/v
1/10= 1/v
therefor v = +10cm
nature of image is virtual and erect.
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