An object is placed at a distance of 30 cm from a convex mirror of focal length 15 cm. The image formed is (a) 20 cm from the pole (b) -10 cm from the pole (c) + 10 cm from the pole (d) +60 cm from the pole
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Answer:Here, u=−30cm,f=15cm
From 1v=1f−1u=115−1−30=330=110
v=10cm.
The image is virtual, erect, smaller in size and at a distance of 10cm from the pole of the mirror at the back of the mirror.
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