an object is projected with a velocity of 20 metre per second making an angle of 45 degree with horizontal equation of trajectory is,h is equal to a x minus b x square where h is height and x is horizontal distance, A and B are constants the ratio of A :B is
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Equation of projectile= xtan0-gx^2/
2u^2cos^2theta (compare with)
Gives 1/1/40=40/1
2u^2cos^2theta (compare with)
Gives 1/1/40=40/1
raazim03:
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Given :-
Velocity of object = u = 20 ms-¹.
Angle of Projection = Ø = 45°
h = Ax - Bx² ------(1)
y = x tanØ - gx²/2u²Cos²Ø -----(2)
Comparing both the equations, we get,
A = tanØ
B = g/2u²Cos²Ø
A/B = tanØ × 2u²Cos²Ø/g
A/B = tan 45° × 2 (20)² × (1/√2)²/10
A/B = (2 × 400/2)/10
A/B = 40/1
A:B = 40:1
Hence,
Ratio of A:B = 40:1
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