Question

an object is thrown vertically upward and Rises to a height of 10 M calculate 1 the velocity with which the object was thrown upward and second the time taken by the object to reach the highest point​

Answer 1

Explanation:

Given,

Height h = 10 cm = 0.1 m

At maximum height, final velocity V = 0

Apply second kinematic equation

V ² - U² = 2ah

0 - U² = 2 ( - g ) × h

U = √2gh  =  √2 × 10 × 0.1 = √2 m/s

Apply first kinematic equation

V = U + at

0 = U - gt

t = U/g = √2 /10 ≅ 0.14 sec

Initial velocity is √2  m/s  and time required to reach maximum height is 0.14 sec