Question

An object is thrown vertically upward with initial velocity of 100m/s find _______________________a) time taken to reach maximum height________b) maximum height reached________c) velocity after 5 seconds

--------------g= 9.8 m/s

Answer 1

Hey user !!!

From 1 equation,, of motion,, we have

V=u+gt ( as g=9.8)
0= 100+9.8×time
= 109.8×time
= time = 110 secs ( approx)

Now ,,we know that,,
Speed= dist÷time
=100= dist÷110
dist= speed ×time = 11,000 meteres..

Theirfore,,The maximum height the object reach is 11000 meters..( approx) ...

Now,, from 1st equation,,
V= u+gt = v= 100+9.8×5 = 149m/s..

HOPE IT HELPS U
PLZ MARK IT AS BRAINLIEST ..
THANKS..