Question

slove for x: 3x2-6x +2=0

Answer 1

Hey !!!
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Here is your answer
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3x2 - 6x + 2 = 0
3x2 - 3x - 2x + 2 = 0
3x ( x - 1 ) - 2 ( x - 1 )= 0

(3x - 2 ) ( x - 1 )

Answer 2

Answer

$\bf \therefore x= \dfrac{3+\sqrt{3}}{3} \:Or\:\dfrac{3-\sqrt{3}}{3}$

• Given

$\sf{ 3x^2-6x+2}=0$

• To find

x=?

Explanation

$\sf{ 3x^2-6x+2}=0$

On comparing equation to the standard form we get

a =3 b=-6 c=2

By Quadratic formula we get

$\bf x= \dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

$\sf x= \dfrac{-(-6)\pm\sqrt{-6^2-4\times3\times2}}{2\times3}\\\\ \longrightarrow x=\dfrac{6\pm\sqrt{36-24}}{6}\\\\\longrightarrow x=\dfrac{6\pm\sqrt{12}}{6}\\\\\longrightarrow x=\dfrac{6\pm\sqrt{2\times2\times3}}{6}\\\\\longrightarrow x=\dfrac{6\pm2\sqrt{3}}{6}\\\\\longrightarrow x=\dfrac{6\pm2\sqrt{3}}{6}$

$\sf\longrightarrow x=\dfrac{3\:\pm\sqrt{3}}{3}\\\\\bf \therefore x= \dfrac{3+\sqrt{3}}{3} \:Or\:\dfrac{3-\sqrt{3}}{3}$

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