Question

An object is thrown vertically upwards and rises to a height of 20 m. Calculate the velocity with which the object was thrown upwards.( g=10 m/s2)
Ans Please​

Answer 1

Answer:

20m/s

Explanation:

v=

$\sqrt{2 \times 10 \times 20 = \sqrt{400 = 20} }$

Answer 2

Answer:

Given :-

• An object is thrown vertically upwards and rises to a height of 20 m.

To Find :-

• Calculate the velocity with which the object was thrown upwards.

Formula Used :-

$\clubsuit$ Third Equation Of Motion Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{v^2 =\: u^2 + 2gh}}}\: \: \: \bigstar$

where,

• v = Final Velocity
• u = Initial Velocity
• g = Acceleration due to gravity
• h = Height

Solution :-

Given :

• Final Velocity = 0 m/s
• Acceleration due to gravity = 10 m/s²
• Height = 20 m

According to the question by using the formula we get,

$\implies \bf v^2 =\: u^2 + 2gh$

$\implies \sf (0)^2 =\: u^2 + 2(- 10)(20)$

$\implies \sf 0 =\: u^2 + (- 400)$

$\implies \sf 0 =\: u^2 - 400$

$\implies \sf 0 - u^2 =\: - 200$

$\implies \sf {\cancel{-}} u^2 =\: {\cancel{-}} 400$

$\implies \sf u^2 =\: 400$

$\implies \sf u =\: \sqrt{400}$

$\implies \sf\bold{\red{u =\: 20\: m/s}}$

$\therefore$ The velocity with which the object was thrown upwards is 20 m/s .

▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃