An object moves in simple harmonic motion with period 6 seconds and amplitude . At time t=0 seconds, its displacement d from rest is 0 cm , and initially it moves in a positive direction.
Give the equation modeling the displacement d as a function of time t .
d=
Answers
Answered by
0
Answer:
Midline will be at -13 which is your vertical shift(d)
Amplitude (a) -s 13 si will move up to 0, back to midline(-13), down to -26 and then back to midline to complete the cycle. This would conform to a sine graph
There is no phase shift
Period is 6 minutes so b= 2pi/6 or pi/3
Equation therefor is y= 13sin[(pi/3)x] -13
Similar questions