Question

An object of height 2 cm is placed at a distance of 15 cm from a concave lens

Answer 1

Answer:

please complete the question❓❓❓

Answer 2

Explanation:

Here ,

h1 = 2cm , u = -15 , P = -10 D , h2 = ?

Now,

f = 100/p = 100/-10 = -10 cm

As

1/v - 1/u = 1/f ,

1/v + 1/15 = 1/-10

1/v = -1/10 - 1/15 = -3-2/30

1/v = -5/30

1/v = -1/6

v = -6 cm

As v is negative , image is virtual

As, m = h2/h1 = v/u , h2/2 = -6/-15 => h2 = 0.8 cm.

As h2 is +ve , image is erect.