An object of mass 100kg is at a retain height above the ground. If the potential energy of the object is 900J find the height at which the object is placed(g=10/s^2)
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let h be the height of the object.
we know
PE = mgh
h = PE / mg
= 900/ (100x10)
= 0.9 m
we know
PE = mgh
h = PE / mg
= 900/ (100x10)
= 0.9 m
kanishka2004kannan:
ty
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