Question

An object of mass 40 kg is raised to height 5m above ground .What is the potential energy ?If the object is allowed to fall find it's kinetic energy when it's half way through ?​

Answer 1

Gravitational potential energy = mgh = 40*10*5 = 2000 Joules

Now,
Kinetic energy = 1/2*m*v^2

So, we need to find the velocity of the object when it's half way through
that means distance (s) = 5/2 = 2.5 metres

V^2 = u^2 + 2gs , here u is zero since the object is at rest initially.

So,
v^2 = 2*5/2*10 = 50 m^2/s^2

Now,
Kinetic energy = 1/2*m*v^2 = 1/2*40*50 = 1000 Joules

Answer 2

_/\_Hello mate__here is your answer--

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Given:-

m = 40 kg

g = 9.8 m/s^2

h = 5 m

We know that,

potential energy = mgh

= 40 × 9.8 × 5 J

= 1960 J

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♦♦The total mechanical energy (Kinetic and potential energy) of an object remains constant. (law of conservation of energy)

Therefore, when the object is half-way down, its potential energy become half the original energy and remaining half converted into kinetic energy.

Hence, the kinetic energy = ½ (1960) J = 980 J

I hope, this will help you.☺

Thank you______❤

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