Question

An object of size 2.0cm is placed perpendicular to the principal axis of a concave mirror. the distance of the object from the mirror equals the radius of curvature. the size of the image will be ​

Answer 1

Answer:

Explanation:

Distance of object from the mirror, u=−30

Distance of image from the mirror, v=−60 , image is real.

Now we know  magnification ratio m=−u /v

m=−  −30 /−60

m=−2

Height of object h=2cm

Image height h1    =m×h=−2×2=−4cm

Height of image is 4 cm and its inverted .

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Answer 2

Answer

The size of the image will  be 2.0 cm.

V=U(given)

m=-v/u

m= - 1

m=h`/h

-1=h`/2

h`=-2

h=2cm