Question

An object placed at a distance of 30cm in front of a concave mirror of focal length 15 find the image position and state whether its virtual or erect​

Answer 1

Answer:

• Image Position is 10 cm

• The image formed is Real and Inverted.

Explanation:

Given:-

• Focal length of Concave Mirror ,f = 15 cm

• Object Distance ,u = -30

To Find:-

• Image Position ,v

Solution:-

Using Mirror Formula

• 1/v + 1/u = 1/f

where,

v is the Image Position

u is the object distance

f is the focal length

Substitute the value we get

→ 1/v = 1/f -1/u

→ 1/v = 1/15 - 1/(-30)

→ 1/v = 1/15 + 1/30

→ 1/v = 2+1/30

→ 1/v = 3/30

→ 1/v = 1/10

→ v = 10cm

Therefore, the image position is 10 cm.

The image formed is Real and Inverted .

Answer 2

$\huge{\boxed{\rm{Question}}}$

An object placed at a distance of -30 cm in front of a concave mirror of focal length 15 find the image position and state whether its virtual or erect.

$\huge{\boxed{\rm{Answer}}}$

$\large{\boxed{\boxed{\sf{Given \: that}}}}$

• Focal length of the concave mirror is 15 cm.

• Distance of the object is -30 cm

$\large{\boxed{\boxed{\sf{To \: find}}}}$

• The image position

• State whether it's erect or virtual.

$\large{\boxed{\boxed{\sf{Solution}}}}$

• Position of image is 10 cm.

• The image is inverted and real.

$\large{\boxed{\boxed{\sf{We \: also \: write \: as}}}}$

• Image position as v.

• Object distance as u.

• Focal length as f.

$\large{\boxed{\boxed{\sf{What \: the \: question \: says}}}}$

$\large{\boxed{\boxed{\sf{Let's \: understand \: the \: concept \: 1st}}}}$

• This question says that a object is placed at a distance of -30 cm in front of a concave mirror and it's focal length is 15 cm afterthat it's ask us to find the image position and state whether its virtual or erect.

$\large{\boxed{\boxed{\sf{How \: to \: do \: this \: question}}}}$

$\large{\boxed{\boxed{\sf{Let's \: see \: the \: procedure \: now}}}}$

• To solve this question we have to know the formula of mirror and we already know this. By this rule we have to put the values. Afterthat we get our result that is 10 cm afterthat we get our final result . And by knowing that we know that the image is real and inverted.

$\large{\boxed{\boxed{\sf{Full \: solution}}}}$

To solve this question we have to use the formula of mirror and we know what is the formula of mirror ! The formula is given below ✍

• 1/v + 1/u = 1/f

Where,

• v means position of the image.

• u means the distance of the object.

• f means focal length.

Putting the values according to this formula we get the following results →

• 1/v + 1/u = 1/f

• 1/v = 1/15 - 1/u

• 1/v = 1/15 -1/(-30)

• 1/v = 1/15 + 1/30

• 1/v = 2+1/30

• 1/v = 3/30

• 1/v = 1/10

• v = 10

Hence, the position of the image is 10 cm.

The image formed is real and inverted.