Question

an object projected vertically up from the top of a tower then find the ratio of the distance travelled by it the last second and distance travel by 2 seconds of its motion​

Answer 1

Answer:

bro can you send the full question

its incorrect

Answer 2

4.9m

A body thrown upwards will decelerate downwards at 1g = 9.8m/s²

When it reaches the apex of the throw, it will be at rest. During the last second it decelerated at 1g for 1 second.

To calculate how far it travelled in the 1 second at 1g deceleration, we can calculate how far it would travel from rest in 1s at 9.8m/s² using the formula:

S = ut + ½at²

S=distance travelled, u=start speed (0), a = acceleration = 9.8, t = time = 1

Which gives a figure of:

0*1 + ½*9.8*1² = 4.9m