Question

An object which is initially at rest,accelerates at a rate of 4 m/s^2. Its final position is 6 m from its initial position at the end of that acceleration. For how much time did it accelerate?

PLEASE ANSWER!!!

Answer 1

Answer:

Solving for Final Position with Constant Acceleration

Ashley❤

Explanation:

Answer 2

Let the time be = t

Initial velocity = 0 m/s [Rest]

Acceleration = 4 m/s²

Distance covered = 6 m

We know,

s = ut + ½at²

⟹ s = ½at²

⟹ t² = 2s/a

⟹ t² = [2(6 m)]/(4 m/s²)

⟹ t² = 3 s²

⟹ t = √3s²

⟹ t = √(3) seconds

∴ For √3 seconds, it accelerated.

[Note: √3 = 1.732.]