Question

An observer 1.7 m tall is 20√3 m away from a tower. The angle of elevation from eye of observer to top of tower is 30 degree. Find the height of tower​

Answer 1

Answer:

21.7

Step-by-step explanation:

tan 30` = 1/√3 = perpendicular / base

1/√3 = p / 20√3

p = 20√3 / √3

p = 20 + 1.7

p = 21.7 m

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Answer 2

Solution. Let AB be the height of the observer and EC be the height of the tower. Let ED be h m. Hence, the height of the tower is 21.7 m.