Question

An observer of height 1.8m is 13.2m away from a palm tree. The angle of evevation of the top of the tree from his eyes is 45°. What is the height of the palm tree

Answer 1

Answer:

Height of observer=AE

=1.8 m

ED=AC

=13.2 m

In △ABC,

tan45

∘

1

BC

=

AC

BC

=

13.2

BC

=13.2 m

The height of the palm tree will be equal to BD. So,

BD

=BC+CD

=13.2+AE

=13.2+1.8

=15 m

So, the height of the palm tree is equal to 15 m.