An oil funnel made of tin sheet consists of a
10 cm long cylindrical portion attached to a
frustum of a cone. If the total height is 22 cm,
diameter of the cylindrical portion is 8 cm and
the diameter of the top of the funnel is 18 cm,
find the area of the tin sheet required to make
the funnel.
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Answer:
Given:
Radius (R) of upper circular end of frustum part = 218=9 cm
Radius (r) of lower circular end of frustum part = Radius of circular end of cylindrical part =28=4 cm
Height (h1) of frustum part =22−10=12 cm
Height (h2) of cylindrical part =10 cm
Slant height (l) of frustum part = (R−r)2+h12=(9−4)2+122=25+144
=169=13 cm
Area of tin sheet required = CSA of frustum part + CSA of cylindrical part
=π(R+r)l+2πrh2
=722×(9+4)×13+2×722×4×10
=722[169+80]=722×249
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