An open box with a square base is to be made out of a given quantity of card board of
area c² square units. Show that the maximum volume of the box is c³/6√3 cubic units.
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The area of the square piece is given to be c2 square units.
Since the base is a square, let the length and breadth of the resulting box be l and the height be h.
Therefore, l2+4lh=c2, equating the areas.
Also, the volume of the box is thus given by length × breadth × height = l2h
We can write the volume only in terms of l as l2×4lc2−l2=4lc2−l3
Differentiating this w.r.t l and equating it to zero, we get c2−3l2=0
⇒l=3c2
The volume thus becomes 4lc2−l3=3c2×4c2−3c2
=
=63c3
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