an ore contains 12% copper how many kilograms of those are required to get 69 kg of copper
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1 kg of copper requires x kg ore = 12%
(1/x)×100 = 12
x = 100/12
x = 25/3
1 kg of copper requires 25/3 kg of ore ;
therefore 69 kg of copper requires
= 69 × (25/3)
= 23 × 25
= 575 kg
__________
Hence your answer is 575 kg
(1/x)×100 = 12
x = 100/12
x = 25/3
1 kg of copper requires 25/3 kg of ore ;
therefore 69 kg of copper requires
= 69 × (25/3)
= 23 × 25
= 575 kg
__________
Hence your answer is 575 kg
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