An ore contains 8% zinc. How many kgs of the ore will be required to get 2.8 kg of zinc?
Answers
Answered by
21
Answer:35kg
Step-by-step explanation:
Zinc in ore = 8%
Zinc in 1kg ore= 8/100x1kg=0.08kg
2.8/0.08 = 35
Therefore 35 kg ore is required
Answered by
11
Answer:
35 kg
Step-by-step explanation:
Percentage of zinc present in the ore = 8%
Amount of zinc = 2.8 kg
Let the amount of ore be = x
Amount of ore required =
8% of x = 2.8 kg
⇒ 8/100 × x = 2.8
⇒ x = 28 × 100/8 × 10 = 35
∴ 35 kg of ore will be required to get 2.8 kg of zinc.
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