an ore on treated with dilute sulphuric acid gives out brisk effervescence of a colorless gas which turns limewater milky. which type of ore it is? name and describe the method you will prefer to oxidize the above-described ore.
Answers
1
Secondary SchoolChemistry 5 points
An ore on treatment with dilute hydrochloric acid produces brisk effervescence to produce a colorless and odourless gas . What type of ore is this? What operation will be required to obtain metal from it?
Ask for details Follow Report by Parthkoshti9748 15.02.2018
Answers
vishalkhurana1
vishalkhurana1 Expert
It is a carbonate ore because it produce CO2 with brisk effervescence.
It should be first calciniced and then reduced to obtain metal
0.0
27 votes
Comments Report
BarrettArcher Ambitious
Answer : The type of ore is, carbonate ore. The operation required to obtained metal from it will be, calcination process.
Explanation :
When an ore on the treatment with the dilute hydrochloric acid produces brisk effervescence to produce a colorless and odorless gas then the ore should be carbonate ore. The operation required to obtained metal from it will be, calcination process.
Calcination process : When the metal carbonate on treatment with the dilute hydrochloric acid, it releases carbon dioxide as a colorless and odorless gas with brisk effervescence. Hence, by the calcination process the metal carbonate ore are converted to their metal oxides.
The reactions involved are :
(1) The metal carbonate ore on heating gives metal oxide and carbon dioxide.
ZnCO_3(S)\overset{\Delta}\rightarrow ZnO(s)+CO_2(g)
(2) The reduction of metal oxide with the carbon to give metal and carbon monoxide as a gas.
ZnO(s)+C(s)\overset{\Delta}\rightarrow Zn(s)_CO(g)