Physics, asked by rumaanahashmi9318, 1 year ago

An organ pipe closed at one end has fundamental frequency of 1500Hz. The maximum number of overtone generated by this pipe which a normal person can hear is :

Answers

Answered by susain2001
17

This is a different approach to the question. Hope this helps.

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Answered by aliyasubeer
0

Answer:

The maximum number of overtone generated by this pipe which a normal person can hear is 6.

Explanation:

Concept: fundamental frequency of a closed pipe=v/4L Where v be the velocity of pipe and L be the length of the pipe.

Given data:

  • Fundamental frequency of closed pipe: 1500Hz.
  • Maximum frequency that a human ear can hear: 20KHz
  • nth frequency of closed pipe= \frac{(2n+1)V}{4L}

                                                          = \frac{(2n+1)1500}{4L}

Equate nth frequency with maximum frequency

                                         20000=(2n+1)1500\\\\20000={(2n+1)1500\\\\

                                         2n+1=13.33( $ don't take decimal. Take 13.)\\2n=12\\n=6

The maximum number of overtone generated by this pipe which a normal person can hear is 6.

                                               

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