Question

An organic compound ‘A’ on treatment with NH₃ gives ‘B’
which on heating gives ‘C’, ‘C’ when treated with Br₂ in the
presence of KOH produces ethylamine. Compound ‘A’ is:
(a) CH₃COOH (b) CH₃ CH₂ CH₂ COOH
(c) CH₃ – CHCOOH (d) CH₃CH₂COOH
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CH₃

Answer 1

Answer:

please forgive me I don't know this answer.....

Answer 2

Compound ‘A’ is:

• An organic compound ‘A’ on treatment with NH₃ gives ‘B’ which on heating gives ‘C’, ‘C’ when treated with Br₂ in the presence of KOH produces ethylamine.

• A + NH₃ → B + ∆ → C + Br₂ + KOH → CH₃CH₂NH₂

• We know that, C undergoes Hoffman bromamide reaction

• C must be Alkanamide.

• We get ethanamine as final product therefore C is propanamide.

• CH₃CH₂COOH +NH₃ → CH₃CH₂COO⁻ NH4⁺ → CH₃CH₂COO NH₂

• Hence, Compound 'A' is Propanoic acid CH₃ CH₂ CH₂ COOH