Question

In Cannizzaro reaction given below
2PhCHO □(→┴:OH)PhCH₂ OH + PhCO₂⊝
the slowest step is :
(a) the transfer of hydride to the carbonyl group
(b) the abstraction of proton from the carboxylic group
(c) the deprotonation of Ph CH₂OH
⊝
(d) the attack of : OH at the carboxyl group

Answer 1

Answer:

please forgive me I don't know this answer...

Answer 2

In any given cannizaro reaction the step including transfer of hydride ion to the carbonyl group is the slowest step.

• A given complex reaction can be broken down into a number of steps involving elementary reactions.
• The slowest step is the rate determining step of the given complex reaction.
• Since, the transfer of hydride ion tothe carbonyl group is the slowest step of the cannizaro reaction , is is also the rate determining step.