an unknown gas shows a density of 3 gram per litre at 273 degree Celsius and 1140 mm of HG pressure what is the gram molecular mass of this gas
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According to the Charles’ Law, the volume of 1 litre of gas at standard temperature can be found with the formula V1/T1 = V2/T2.
Here, T1 is 273C that should be converted to 546K and T2 is the standard temperature of 273K.
Thus in this case, 1 /546 = V2/273. So V2 = 0.5 liters.
So if 1 liter volume of gas weighs 3 gm, then 0. 5 liter should weigh 1.5 gm in standard temperature.
Here, T1 is 273C that should be converted to 546K and T2 is the standard temperature of 273K.
Thus in this case, 1 /546 = V2/273. So V2 = 0.5 liters.
So if 1 liter volume of gas weighs 3 gm, then 0. 5 liter should weigh 1.5 gm in standard temperature.
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