an urn contain 4 white and 6 red balls .four balls are drawn at random without replacement from the urn .find the probability distribution of number of white ball
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POSSIBLE OUTCOMES = NO OF RED BALL + NO OF WHITE BALL = 6+4 = 10
FAVOURABLE OUTCOMES = 4
P(E) GETTING A WHITE BALL = FAVOURABLE OUTCOMES/POSSIBLE OUTCOMES = 4/6 = 2/3
FAVOURABLE OUTCOMES = 4
P(E) GETTING A WHITE BALL = FAVOURABLE OUTCOMES/POSSIBLE OUTCOMES = 4/6 = 2/3
cristal:
p(1)=8/21
Okay Sorry for giving wrong answer
forgive me
ye kon se class ka question hai
12
but i am in 10th
sorry for wrong answer cristal
its m
its k
:-)
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