Question

An urn contains 6 balls of which 2 are red and 4 are black.2 balls are drwan at random .Find probability that they are of different colours

Answer 1

Answer:

8/15

Step-by-step explanation:

let me explain whole concept, you write your owns steps for answer

given : total balls= 6

red balls = 2

black balls= 4

balls drawn are 2

now think you are drawing the balls ok,think u drawn 2 balls at random

(1) both are black then

(2) both are red

(3) first is red , second is black

(4) first is black, second is red

according to question you have to write answer if both balls of different colours

then which event are possible (3)&(4)

will solve it one by one

(3) first is red , second is black

total balls was 6 , u drawn first ball that was of red

it means red balls can be two because in question they have mentioned two red balls

so probablility of first ball becomes 2/6

now u already drawn one ball next u gng to draw one more ball ,then it means total balls will reduce from 6 to 5 ,think second ball is black,how many black balls you have that is 4 ,hence probability of second ball becomes 4/5

total probability= (2/6)*(4/5)=4/15

(4) first is black, second is red

same concept as above you apply

you will get = (4/6)*(2/5)= 4/15

total probability = (4/15)+(4/15)= 8/15

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