Question

and B are (2,0) and (-2, 4) respectively
the coordinates of point P.
If PA=PB and the coordinates ofpoint A
and ifP lies on the y axis then calculate​

Answer 1

Answer:

Answer is ( 0, 2)

Step-by-step explanation:

The given points are A(2,0) and B(-2, 4)

Since, point P lies on axis of Y, hence it's X- coordinate will be zero.

∴ Let coordinates of P are ( 0, y).

As given in the problem,

PA = PB

$⟹ \sqrt{(2 - 0 {) }^{2} + ( {0 - y)}^{2} } \\ \: \: \: \: \: = \sqrt{( - 2 - 0 {)}^{2} + {(4 - y)}^{2} }$

Squaring both sides,

$4 + {y}^{2} = 4 + ( {4 - y)}^{2}$

$⟹ {y}^{2} = 16 + {y}^{2} - 8y$

$⟹8y = 16$

$∴ \: \: \: \: \: y = \frac{16}{8} = 2$

Hence, the coordinates of P are ( 0, 2).