And B throw a pair of dice.if A throws 9, find B's chance of throwing a higher number.
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Plz recheck the question, I think it's incomplete
sneha270603:
Ok sorry, I will try to understand it:)
the answer is 1/6
as there will be 6 outcomes
(4,6) (6,4) (5,5) (6,6) (5,6) (6,5)
yes 1/6
total outcomes is 36...so 6/36
Given that ‘A’ throws 9 and B throws a higher number than 9 That is B throws 10 or 11 or 12 Total number of outcomes on throwing 2 dices = 6 × 6 = 36 Favourable outcomes are: {(4,6) (5,5), (6,4), (5,6), (6,5), (6,6)} Number of favourable outcomes = 6 ∴ Probability of B throwing a number greater than 9 = (6/36) = 1/6
Okk
Thankyou so much
✌️
Answered by
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one third chance
.........
.........
one sixth chance
How one third or even one sixth?
Plz explain
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