and heap of rice is in the form of a cone of base diameter 24 M and height 3.5 M find the volume of the Rise and how much Canvas is required to cover does the heat
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GIVEN:
Diameter of Cone = 24 m
Height of Cone = 3.5 m
Radius of Cone = diameter/2 = 24/2 = 12 m
Volume of rice = volume of cone
volume of cone = ⅓ πr²h
Volume of rice = 1/3 × 22/7 × (12)² × 3.5
Volume of rice = 1/3 × 22/7 × 144 × 7/2
= 48 × 11 = 528 m³
Volume of rice = 528 m³
Area of canvas cloth = curved surface area of cone = πrl
Slant Height ( l )= √r² + h²
= √12² + 3.5²
= √144 + 12.25
= √156.25 = 12.5 m
Slant Height ( l )= 12.5 m
Area of canvas cloth = πrl
= 22/7 × 12 × 12.5
= 471.42 m²
Hence, the volume of rice is 528 m³ & Area of canvas cloth is 471.42 m²
HOPE THIS WILL HELP YOU….
Diameter of Cone = 24 m
Height of Cone = 3.5 m
Radius of Cone = diameter/2 = 24/2 = 12 m
Volume of rice = volume of cone
volume of cone = ⅓ πr²h
Volume of rice = 1/3 × 22/7 × (12)² × 3.5
Volume of rice = 1/3 × 22/7 × 144 × 7/2
= 48 × 11 = 528 m³
Volume of rice = 528 m³
Area of canvas cloth = curved surface area of cone = πrl
Slant Height ( l )= √r² + h²
= √12² + 3.5²
= √144 + 12.25
= √156.25 = 12.5 m
Slant Height ( l )= 12.5 m
Area of canvas cloth = πrl
= 22/7 × 12 × 12.5
= 471.42 m²
Hence, the volume of rice is 528 m³ & Area of canvas cloth is 471.42 m²
HOPE THIS WILL HELP YOU….
Answered by
2
Given:
Diameter = 24 m
Height = 3.5 m
To find:
Volume
Cloth required to cover
Solution:
Volume = 1 / 3 * π * ( radius )^2 * height
Here,
Radius = diameter / 2
Radius = 12 m
Substituting,
1 / 3 * 3.14 * ( 12 )^2 * 3.5
Volume = 528 cu.m
The cloth required to cover = π * radius * length
To find length,
Length = √ ( height )^2 + ( radius )^2
Substituting,
√ ( 3.5 )^2 + ( 12 )^2
Hence,
Length = 12.5 m
3.14 * 12 * 12.5
The cloth required = 471.4 sq.m
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