andy has twice marbles as many as pandy have and sand has half as many as andy and pandy put together. if andy has75 marbles more than sandy how many marbles each has
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Answered by
4
hi Flower,
Let number of marbles with Andy,Sandy and Pandy be a,s,p respectively
Given
Andy has twice marbles as many as pandy
a = 2p
sandy has half as many as andy and pandy put together
s = 1/2(a+p)
andy has75 marbles more than sandy
a = 75+s
solving
put a=2p in s = 1/2(a+p)
s = 1/2(3p)
s = 3p/2
put s value in a = 75+s
a= 75+3p/2
now also a = 2p
so equating for 'a' values
2p = 75+3p/2
p (2 - 3/2 ) = 75
p/2 = 75
p = 150
a = 2p = 300
s = 3p/2 = 450 / 2 = 225
p = 150
a = 300
s = 225
Hope it helped
Let me know if any doubts.
Cheers !!!
Let number of marbles with Andy,Sandy and Pandy be a,s,p respectively
Given
Andy has twice marbles as many as pandy
a = 2p
sandy has half as many as andy and pandy put together
s = 1/2(a+p)
andy has75 marbles more than sandy
a = 75+s
solving
put a=2p in s = 1/2(a+p)
s = 1/2(3p)
s = 3p/2
put s value in a = 75+s
a= 75+3p/2
now also a = 2p
so equating for 'a' values
2p = 75+3p/2
p (2 - 3/2 ) = 75
p/2 = 75
p = 150
a = 2p = 300
s = 3p/2 = 450 / 2 = 225
p = 150
a = 300
s = 225
Hope it helped
Let me know if any doubts.
Cheers !!!
jish4you:
did u understand how i got those initial equations ?
Answered by
3
Ok attached is the solution
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