Math, asked by flower99, 1 year ago

andy has twice marbles as many as pandy have and sand has half as many as andy and pandy put together. if andy has75 marbles more than sandy how many marbles each has

Answers

Answered by jish4you
4
hi Flower,

Let number of marbles with Andy,Sandy and Pandy be a,s,p respectively
Given

Andy has twice marbles as many as pandy
a = 2p

sandy has half as many as andy and pandy put together
s = 1/2(a+p)

andy has75 marbles more than sandy
a = 75+s

solving
put a=2p in s = 1/2(a+p)
s = 1/2(3p)
s = 3p/2

put s value in a = 75+s
a= 75+3p/2
now also a = 2p

so equating for 'a' values
2p = 75+3p/2
p (2 - 3/2 ) = 75
p/2 = 75
p = 150
a = 2p = 300
s = 3p/2 = 450 / 2 = 225 


p = 150
a = 300
s = 225

Hope it helped
Let me know if any doubts.
Cheers !!!

jish4you: did u understand how i got those initial equations ?
flower99: yes i want all the steps
flower99: no i did not understand
jish4you: wait
jish4you: now?
flower99: thanks alot
flower99: it is all clear now
jish4you: pheww haha
jish4you: good to know
jish4you: pls mark it as brainliest if you find my solution helpful. I will be appreciated. thank you
Answered by sanskarsingh98765432
3

Ok attached is the solution

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