Question

Aneesh spend 3/7 of his money on a shirt & 1/2 of the remainder on a pair of trousers. If he had $23 left, how much did Aneesh spend altogether?

Answer 1

$<b><u>Let us take that he had x .</b></u>$

Money spent on shirt = 3/7of x. = $3x/7.

Money left with her = x - 3x/7 = $4x/7.

Money spent on trousers = 1/2of 4x/7 = $4x/14.

Money left with her = $23.

So Atq , $(3x/7+4x/14+23).=$x.

or$10x/14+23=$x.

or$23. =$(x-10x/14)

or$23. =$2x/7

$<b>Therefore x. =23×7/2= 80.5$


$<marquee behavior="alternate">So he had 80.5$

Answer 2

Answer:

$57.50 spend altogether.

Step-by-step explanation:

Let total money Aneesh has be x

Aneesh spend $\frac{3}{7}$ of his money on a shirt,

Spend on shirt  $=\frac{3}{7}x$

Remaining money  $=x-\frac{3}{7}x=\frac{4}{7}x$

Aneesh spend $\frac{1}{2}$ of of the remainder on a pair of trousers.

Spend on trouser   $=\frac{1}{2}\times \frac{4}{7}x=\frac{2}{7}x$

He had left $23

According to question,

$\frac{3}{7}x+\frac{2}{7}x+23=x$

Multiply by 7 to each term of the equation

$7\times \frac{3}{7}x+7\times \frac{2}{7}x+7\times 23=7x$

$3x+2x+161=7x$

$2x=161$

x=$80.50

Aneesh Spend on shopping = 80.50-23.00 = $57.50