angle A=30°, then show that cos 3A = 4 COS^3^A - 3 COS A
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Step-by-step explanation:
Given that ∠A = 30°
LHS ---- 3A = 3 × 30 = 90°
cos 90° = 0
RHS ----- 4cos³A - 3cosA
= 4 cos³ 30° - 3 cos30°
= 4 [√3 /2]³ - 3 [√3 /2]
= 4 × 3√3 /8 - 3√3 /2
= 3√3 /2 - 3√3 /2
= 0
LHS = RHS Hence Proved
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