angle bcd and bdc plese help
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rajroy47:
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the answer is angle bcd= 25° and angle bdc= 125°
right answer
nope angle abd is 30° and khushi has taken angle abc as 30°
mine is correct
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angle abd + dbc = abc
30 + 30 = abc ( bd is bisector )
In triangle abc
abc + acb + bac = 180° (ASP)
60° + acb + 70° = 180°
acb = 180° - 70° - 60°
acb = 50°
angle dbc = 30°
dcb = 25° ( dc is bisector )
In triangle dbc
dbc + dcb + d = 180° (ASP)
30°+ 25° + d = 180°
55° + d = 180°
d = 180° - 55°
d = 125°
30 + 30 = abc ( bd is bisector )
In triangle abc
abc + acb + bac = 180° (ASP)
60° + acb + 70° = 180°
acb = 180° - 70° - 60°
acb = 50°
angle dbc = 30°
dcb = 25° ( dc is bisector )
In triangle dbc
dbc + dcb + d = 180° (ASP)
30°+ 25° + d = 180°
55° + d = 180°
d = 180° - 55°
d = 125°
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its right answer
yes
ok
no you are wrong
you have taken angle abc as 30°
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