The angle of elevation of top of an electric pole from a point on the ground, which is 40 m away from the foot of the pole, is 30 . Find the height of the electric pole.
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angle = 30°
distance = adjacent = 40m
height = opposite = x
tan30° = 1/√3
=>tan 30° = opp/adj
=>1/√3 = x/40
=>x = 40/√3
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distance = adjacent = 40m
height = opposite = x
tan30° = 1/√3
=>tan 30° = opp/adj
=>1/√3 = x/40
=>x = 40/√3
HOPE IT HELPS
PLZ MARK ME AS BRAINLIEST
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The answer for the question is 40/√3
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