Question

Angle between surfaces x^2+y^2+z^2=9 and z=x^2+y^2-3

Answer 1

x^2+y^2+z^2=9

(put value of z^2 in this equation from second equation)

we get,

x^2+y^2+x^2+y^2-3=9

2x^2+2y^2=9+3

2 (x^2 + y^2) = 12

x^2 + y^2 = 6

(Put this in equation no. 2)

we get,

z^2=6-3

z^2=3

by the way ur question i think is wrong. in 2nd eq. it must be z^2. then you get ur answer.

anyway mark as brainliest if u liked.