angle between
two
vectors
Angle
3i +4j
and
4i-3j is
**
Answers
Answered by
0
Answer:
We could try using the SCALAR PRODUCT between them:
→
v
⋅
→
w
=
∣
∣
→
v
∣
∣
∣
∣
→
w
∣
∣
cos
(
θ
)
=
v
x
w
x
+
v
y
w
y
Where you have that the scalar product is equal to the product of the modulii times the cosine of the angle between the vectors AND equal to the sum of the products between the components of the two vectors, or:
∣
∣
→
v
∣
∣
∣
∣
→
w
∣
∣
cos
(
θ
)
=
v
x
w
x
+
v
y
w
y
Now:
∣
∣
→
v
∣
∣
=
√
3
2
+
4
2
=
√
25
=
5
∣
∣
→
w
∣
∣
=
√
4
2
+
3
2
=
√
25
=
5
v
x
w
x
+
v
y
w
y
=
3
⋅
4
+
4
⋅
3
so:
5
⋅
5
⋅
cos
(
θ
)
=
3
⋅
4
+
4
⋅
3
25
cos
(
θ
)
=
24
θ
=
a
r
cos
(
24
25
)
=
16.26
∘
Similar questions