Angles of quadrilateral so are (4x) , 5 (x+2), (7x -20) and 6(x+3). find :- the value of x- each angle of the quadrilateral
Answers
Answered by
0
Answer:
sum of the angles of = 360°, 4x +5(x+2) + (7x -20) +6(x+3) = 360° = 4x +5x +10+ 7x -20+ 6x + 18 =360° = 22x +8 =360 ° = 22x = 360-8= 22x = 352 Hence x=352/22= 16, 4x = 64 °, 5(x+2) = 90° , 7x-20= 92° and 6(x+3) = 114° Hence, the angles are 64°, 90°, 92° and 114°.
Similar questions