anjou has 28 apples 3/7 of them are rotten apples, find the number of the rotten apples
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Three rotten apples are mixed with seven fresh apples. Find the probability distribution of the number of rotten apples, if three apples are drawn one by with replacement. Find the mean of the number of rotten apples.
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Given Rotten apples −3
Fresh apples −
10
7
p=p(R)=
10
3
q=1−p=1−
10
3
=
10
7
here n=3
p(x)=p(0,1,2,3)
p(0)=
3
c
0
(
10
3
)
0
(
10
7
)
3
=
3
c
0
.
10
3
7
3
=
1000
343
p(1)=
3
c
1
(
10
3
)
1
(
10
7
)
2
=
3
c
1
.
10
3
3.7.7
=
1000
441
p(2)=
3
c
2
(
10
3
)
2
(
10
7
)
1
=
100
3.9.7
=
1000
189
p(3)=
3
c
3
(
10
3
)
3
(
10
7
)
0
=
1000
1.27
=
1000
27
Refer image.
H=∑x.p(x)
=0.(
1000
343
)+1.(
1000
441
)+2.(
1000
189
)+3.(
1000
27
)
=
1000
441+378+81
=
1000
9000
=
10
9
solution