Question

Ans fast plzz...

An object having a velocity 4.0 m/s is accelerated at the rate of 1.2 m/s² for 5.0 s. Find
the distance travelled during the period of acceleration ? Explain plzz...

Answer 1

HEY DEAR HERE IS YOUR ANSWER ✌✌❤❤

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GIVEN :-

initial velocity (u) = 4ms^-1

acceleration (a) = 1.2ms^-2

time (t) = 5s

SOLUTION :-

we know a kinematical equation

s = ut +1/2at ^2

= 4 (5) +1/2 (1.2)(5)^2

= 20 + (0.6)(25)

= 20 + 15

= 35m

there distance = 35m

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