Question

ans it !!!!!!!!!!!☺☺☺☺☺

Answer 1

❤ Saiyaan ❤

Beautiful question ✌

So,

For,

a) Distance travelled = area under the graph

= 1/2*10*12

= 60 m

We know,

Average speed = d/t

= 60/10

= 6 m/s

First one was easy but second one is a bit lengthy,

b) let d1 and d2 be the distance travelled by the particles between time,

So, t1 = 2 to 5 sec

And t2 = 5 to 6 sec respectively.

Total distance in t1,

D = d1 + d2

For d1,

Let u be the velocity after 2 sec

a be the acceleration in 0 to 5 sec,

By equation of motion,

V = u + at

a = 2.4 m/s^2

Again by equation of motion,

V = 4.8m/s

Distance travelled in 3 sec by, (2 to 5 sec)

S1 = ut + 1/2*a*t^2

= 25.2 m

Similarly S2 = 10.8m

Now S = S1+S2

= 36m

So,

Average speed = 36/4

= 9 m/s

♥ Saiyaan ♥