Question

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Answer 1

Answer:  2

Step-by-step explanation:

Given ,

one root of quadratic equation 2x² - px + q = 0 is 2 + √3

then, other root must be (2 - √3)

Now, sum of roots = -coefficient of x/coefficient of x²

(2 + √3) + (2 - √3) = -(-p)/2

⇒ 4 = p/2

⇒p = 8

product of roots = constant/Coefficient of x²

(2 + √3)(2 - √3) = q/2

⇒(2² - √3²) = q/2

⇒ 4 - 3 = q/2

⇒ 1 = q/2

⇒q = 2

=p/q

=8/2

=4