Question

answe pls it's urgent pls pls​

Answer 1

Answer:

here is your answer hope it helps .....

Step-by-step explanation:

In ∆PQC & ∆CRP

PQ=CR (given)

QC=RP (given)

PC=CL (common)

thus , ∆PQC~=∆CRP (BY SSS)

=> <PCQ=<CPR. (BY C.P.C.T )(hence proved)