Question

answer all these 3...!​

Answer 1

Answer:

1. 1/2 Mgl

2. 3) mass is at the lowest point.

3. 1) 2:1

Explanation:

1. Let volume of wire is V , cross sectional area is A and length of wire is already given i.e., L

so, elastic potential energy = 1/2 × stress × strain × V

stress = force applied/area

                   = weight of body/A

                   = Mg/A

strain = change in length/original Length

         = l/L

so,elastic potential energy = 1/2 × Mg/A × l/L × AL

                                            = 1/2 × Mg × l

                                            = 1/2 Mgl

hence, elasticpotential energy is 1/2 Mgl

2. The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.