Answer fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast fast........... .......
Answers
v = 0 + a₁t₁ = 3t₁
v = 3t₁ .......multiplying b/s by 2, we get
2v = 6t₁ ..........(i)
Case.2 : final velocity is zero.
0 = u + a₂t₂ = u + (-2)t₂
-u = -2t₂
u = 2t₂ .......multiplying b/s by 3, we get
3u = 6t₂ ..........(ii)
Adding (i) & (ii), we get
2u + 3v = 6(t₁+t₂) = 6*4 = 24
∴ maximum speed = 24 m/s
mark this answer the brainliest, if you find it so
hope it helps........
Answer:
Case.1 : initial velocity is zero.
v = 0 + a₁t₁ = 3t₁
v = 3t₁ .......multiplying b/s by 2, we get
2v = 6t₁ ..........(i)
Case.2 : final velocity is zero.
0 = u + a₂t₂ = u + (-2)t₂
-u = -2t₂
u = 2t₂ .......multiplying b/s by 3, we get
3u = 6t₂ ..........(ii)
Adding (i) & (ii), we get
2u + 3v = 6(t₁+t₂) = 6*4 = 24
∴ maximum speed = 24 m/s
mark this answer the brainliest, if you find it so
hope it helps........
Explanation:
Case.1 : initial velocity is zero.
v = 0 + a₁t₁ = 3t₁
v = 3t₁ .......multiplying b/s by 2, we get
2v = 6t₁ ..........(i)
Case.2 : final velocity is zero.
0 = u + a₂t₂ = u + (-2)t₂
-u = -2t₂
u = 2t₂ .......multiplying b/s by 3, we get
3u = 6t₂ ..........(ii)
Adding (i) & (ii), we get
2u + 3v = 6(t₁+t₂) = 6*4 = 24
∴ maximum speed = 24 m/s
mark this answer the brainliest, if you find it so
hope it helps........