Math, asked by samir1123, 11 months ago

answer fast please ASAP

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Answered by vishalkumar2806
0

let \: f(x) =  \frac{x { }^{2} }{1 + x {}^{2} }  \\ domain \:  = real \\ as \: 1 + x { }^{2} \: \: never \:  \: be \: zero

for \: range \: put \: f(x) = y \\ y + yx {}^{2}  = x {}^{2}  \\ x {}^{2}  =  \frac{y}{1 - y}  \\ x =  \sqrt{ \frac{y}{1 - y} } \\ range \:  = w \:  - (1)

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