Question

If α,β and ϒ are the zeroes of the polynomial 6x3 + 3x2 -5x +1, then find the value of
1/(α )+1/β +1/ϒ


Help me fast urgent

Answer 1

$\alpha \beta \gamma = \frac{ - d}{a} \\ \alpha \beta + \beta \gamma + \gamma \alpha = \frac{c}{a} \\ p(x) = 6 {x}^{3} + {3x}^{2} - 5x + 1 \\ comparing \\ p(x) = {ax}^{3} + bx {}^{2} + cx + d \\ \frac{1}{ \alpha } + \frac{1}{ \beta } + \frac{1}{ \gamma } = \\ \frac{\alpha \beta + \beta \gamma + \gamma \alpha}{\alpha \beta \gamma} = \frac{ - 5}{ - 1} = 5$

Answer 2

Answer:

hope it may help you.......