Question

answer for this please!

Answer 1

↑ Here is your answer ↓
_____________________________________________________________
_____________________________________________________________

In the given figure, AB Perpendicular to BC, FG Perpendicular to BC and DE perpendicular to AC. Prove that triangle ADE is similar to triangle GCF.

In ΔABC and ΔGFC, 

∠B = ∠E (90°.)
∠C = ∠C (Common.)

∴ ΔABC ~ ΔGFC (AA Criterion) ---(1)

Similarly in ΔABC and ΔAED,

∠B = ∠F (90°.)
∠A = ∠A (Common.)

∴ ΔABC ~ ΔAED ---(2)

From (1) and (2)

ΔADE ~ ΔGCF

____________________________________________________________________________________________________________________________

Glad to help you.
@EmadAhamed